Maths Worksheets For Class 1: Maths Worksheet for Class 1 is a fun way to help young students master basic mathematical skills. These worksheets comprise interesting and intriguing Maths questions for Class 1 children. In Class 1 Maths Worksheets, the main focus is on counting numbers followed by place value concepts. Child will encounter in its math development. When a child can multiply (and divide) without much thinking and without falling back on adding numbers, it will learn all future math topics much easier. Its all related! Children who can not, or have difficulties in reciting the times tables will lack speed and accuracy to master more. Soln: A man can enter the stadium in 4 ways. Again the man can leave the stadium in 9 ways. So, total no.of ways with which a man enters and then leaves the stadium = 4. 9 = 36ways. NOTICE - DATE CHANGE. REGULAR SCHOOL BOARD MEETING. COLVILLE SCHOOL DISTRICT BOARD OF DIRECTORS. The regular scheduled January 27, 2021 school board meeting for the Colville School District will be on Tuesday, January 26, 2021 at 6:00 PM via a remote meeting. Contact Info Phone #: (248)684-8060 E-mail: Andrea.Colville@hvs.org.
1.1
1.
Soln:
A man can enter the stadium in 4 ways. Again the man can leave the stadium in 9 ways.
So, total no.of ways with which a man enters and then leaves the stadium = 4 * 9 = 36ways.
2.
Soln:
There are 6 choices for a student to enter the hostel. There are 5 choices for a student to leave the hostel as different door is to be used.
So, total no.of ways = 6 * 5 = 30.
3.
A man can enter the stadium in 4 ways. Again the man can leave the stadium in 9 ways.
So, total no.of ways with which a man enters and then leaves the stadium = 4 * 9 = 36ways.
2.
Soln:
There are 6 choices for a student to enter the hostel. There are 5 choices for a student to leave the hostel as different door is to be used.
So, total no.of ways = 6 * 5 = 30.
3.
Soln:
There are 7 choices for 1st son, 6 choices for 2nd son and 5 choices for 3rd son.
Now, by the basic principle of counting, the total number of ways of choice = 7 * 6 * 5 = 210.
4.
Soln:
A man can go from city A to city B in 5 ways. As he has to return by a different road, so he can return from city B to city A in 4 ways.
So, total no.of ways by which a man can go from city A to city B and returns by a different road = 5 * 4 = 20 ways.
Old Unit2agendasmrs. Colville's Math Classes
5.
Soln:
A person can go from city A to city B in 5 ways. Again, he can go from city B to city C in 4 ways. So, a person can go from city A to city C in 5 * 4 = 20ways. The person has to return from C to A without driving on the same road twice, So, he can return from city C to city B in 3 ways and from city B to city A in 4 ways.
So, he can return from city C to city A in 3 * 4 = 12 ways.
So, Total no.of ways by which a person can go from city A to city C and return from city C to city A = 20 * 12 = 240 ways.
6.
Soln:
Numbers formed should be of at least 3 digits means they may be of 3 digits, 4 digits, 5 digits or 6 digits.
There are 6 choices for digit in the units place. There are 5 and 4 choices for digits in ten and hundred's place respectively.
So, total number of ways by which 3 digits numbers can be formed = 6.5.4 = 120
Similarly, the total no.of ways by which 4 digits numbers can be formed = 6.5.4.3 = 360.
the total no. of ways by which 5 digits numbers can be formed = 6.5.4.3.2 = 720.
The total no.of ways by which 4 digits numbers can be formed = 6.5.4.3.2.1 = 720.
So, total no.of ways by which the numbers of at least 3 digits can be formed = 120 + 360 + 720 + 720 = 1920.
7.
Old Unit2agendasmrs. Colville's Math Classroom
Soln:
The numbers formed must be of three digits and less than 500, so the digit in the hundred's place should be 1,2,3 or 4. So, there are 4 choices for the digit in the hundred's place. There are 5 choice for the digit in the ten's place. There are 4 choices for the digit in the unit's place.
So, no of ways by which 3 digits numbers les than 500 can be formed = 4.5.4 = 80.
Old Unit2agendasmrs. Colville's Math Class 9
8.
Soln:
The numbers formed should be even. So, the digit in the unit's place must be 2 or 4. So, the digit in unit's place must be 2 or 4. So, for the digit in unit's place, there are 2 choices. So, after fixing the digit in the unit's place, remaining 4 figures can be arranged in P(4,4) ways.
Ie. $frac{{left( 4 right)!}}{{left( {4 - 4} right)!}}$ = $frac{{4!}}{{0!}}$ = $frac{{4{rm{*}}3{rm{*}}2{rm{*}}1}}{1}$ = 24 ways.
So, total no.of ways by which 5 even numbers can be formed = 2 * 24 = 48.
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Soln:
The numbers formed must be of 4 digits. The digit in the thousand's place must always be 4. For this, there is only one choice. After that, n = 6 – 1 = 5, r = 4 – 1 = 3. Then remaining 5 figures can be placed in remaining 3 places in:
Or, P(5,3) ways = $frac{{5!}}{{left( {5 - 3} right)!}}$ = $frac{{5!}}{{2!}}$ = $frac{{5{rm{*}}4{rm{*}}3{rm{*}}2{rm{*}}1}}{{2{rm{*}}1}}$ = 60 ways.
So, Total no.of ways by which 4 digits numbers between 4,000 and 5,000 can be formed = 1 * 60 = 60.
10.
Soln:
For the three digits numbers, there are 5 ways to fill in the 1st place, there are 4 ways to fill in the 2nd place and there are 3 ways to fill in the 3rd place. By the basic principle of counting, number of three digits numbers = 5 * 4 * 3 = 60.
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Again, for three digit numbers which are divisible by 5, the number in the unit place must be 5. So, the unit place can be filled up in 1 way. After filling up the unit place 4 numbers are left. Ten's place can be filled up in 4 ways and hundredths place can be filled up in 3 ways. Then by the basic principle of counting, no.of 3 digits numbers which are divisible by 5 = 1 * 4 * 3 = 12.
